(4z+1)=(13z-8)

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Solution for (4z+1)=(13z-8) equation: 



(4z+1)=(13z-8)

We move all terms to the left:

(4z+1)-((13z-8))=0

We get rid of parentheses

4z-((13z-8))+1=0



We calculate terms in parentheses: -((13z-8)), so:

(13z-8)

We get rid of parentheses

13z-8

Back to the equation:

-(13z-8)



We get rid of parentheses

4z-13z+8+1=0

We add all the numbers together, and all the variables

-9z+9=0

We move all terms containing z to the left, all other terms to the right

-9z=-9

z=-9/-9

z=1

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