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5(x+3)=4-3(x+1)
We move all terms to the left:
5(x+3)-(4-3(x+1))=0
We multiply parentheses
5x-(4-3(x+1))+15=0
We calculate terms in parentheses: -(4-3(x+1)), so:We get rid of parentheses
4-3(x+1)
determiningTheFunctionDomain -3(x+1)+4
We multiply parentheses
-3x-3+4
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
5x+3x-1+15=0
We add all the numbers together, and all the variables
8x+14=0
We move all terms containing x to the left, all other terms to the right
8x=-14
x=-14/8
x=-1+3/4
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