(4z+1)(9-z)=0

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Solution for (4z+1)(9-z)=0 equation:


Simplifying
(4z + 1)(9 + -1z) = 0

Reorder the terms:
(1 + 4z)(9 + -1z) = 0

Multiply (1 + 4z) * (9 + -1z)
(1(9 + -1z) + 4z * (9 + -1z)) = 0
((9 * 1 + -1z * 1) + 4z * (9 + -1z)) = 0
((9 + -1z) + 4z * (9 + -1z)) = 0
(9 + -1z + (9 * 4z + -1z * 4z)) = 0
(9 + -1z + (36z + -4z2)) = 0

Combine like terms: -1z + 36z = 35z
(9 + 35z + -4z2) = 0

Solving
9 + 35z + -4z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(9 + -1z)(1 + 4z) = 0

Subproblem 1

Set the factor '(9 + -1z)' equal to zero and attempt to solve: Simplifying 9 + -1z = 0 Solving 9 + -1z = 0 Move all terms containing z to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1z = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1z = 0 + -9 -1z = 0 + -9 Combine like terms: 0 + -9 = -9 -1z = -9 Divide each side by '-1'. z = 9 Simplifying z = 9

Subproblem 2

Set the factor '(1 + 4z)' equal to zero and attempt to solve: Simplifying 1 + 4z = 0 Solving 1 + 4z = 0 Move all terms containing z to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4z = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4z = 0 + -1 4z = 0 + -1 Combine like terms: 0 + -1 = -1 4z = -1 Divide each side by '4'. z = -0.25 Simplifying z = -0.25

Solution

z = {9, -0.25}

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