3x+10=(x+2)(x+2)

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Solution for 3x+10=(x+2)(x+2) equation: 


Simplifying
3x + 10 = (x + 2)(x + 2)

Reorder the terms:
10 + 3x = (x + 2)(x + 2)

Reorder the terms:
10 + 3x = (2 + x)(x + 2)

Reorder the terms:
10 + 3x = (2 + x)(2 + x)

Multiply (2 + x) * (2 + x)
10 + 3x = (2(2 + x) + x(2 + x))
10 + 3x = ((2 * 2 + x * 2) + x(2 + x))
10 + 3x = ((4 + 2x) + x(2 + x))
10 + 3x = (4 + 2x + (2 * x + x * x))
10 + 3x = (4 + 2x + (2x + x2))

Combine like terms: 2x + 2x = 4x
10 + 3x = (4 + 4x + x2)

Solving
10 + 3x = 4 + 4x + x2

Solving for variable 'x'.

Reorder the terms:
10 + -4 + 3x + -4x + -1x2 = 4 + 4x + x2 + -4 + -4x + -1x2

Combine like terms: 10 + -4 = 6
6 + 3x + -4x + -1x2 = 4 + 4x + x2 + -4 + -4x + -1x2

Combine like terms: 3x + -4x = -1x
6 + -1x + -1x2 = 4 + 4x + x2 + -4 + -4x + -1x2

Reorder the terms:
6 + -1x + -1x2 = 4 + -4 + 4x + -4x + x2 + -1x2

Combine like terms: 4 + -4 = 0
6 + -1x + -1x2 = 0 + 4x + -4x + x2 + -1x2
6 + -1x + -1x2 = 4x + -4x + x2 + -1x2

Combine like terms: 4x + -4x = 0
6 + -1x + -1x2 = 0 + x2 + -1x2
6 + -1x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
6 + -1x + -1x2 = 0

Factor a trinomial.
(2 + -1x)(3 + x) = 0


Subproblem 1
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2

Subproblem 2
Set the factor '(3 + x)' equal to zero and attempt to solve:

Simplifying
3 + x = 0

Solving
3 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + x = 0 + -3
x = 0 + -3

Combine like terms: 0 + -3 = -3
x = -3

Simplifying
x = -3
Solution
x = {2, -3}

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