(4y-3)=2(11y+4)

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Solution for (4y-3)=2(11y+4) equation: 



(4y-3)=2(11y+4)

We move all terms to the left:

(4y-3)-(2(11y+4))=0

We get rid of parentheses

4y-(2(11y+4))-3=0



We calculate terms in parentheses: -(2(11y+4)), so:

2(11y+4)

We multiply parentheses

22y+8

Back to the equation:

-(22y+8)



We get rid of parentheses

4y-22y-8-3=0

We add all the numbers together, and all the variables

-18y-11=0

We move all terms containing y to the left, all other terms to the right

-18y=11

y=11/-18

y=-11/18

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