8(4y-3)=2(11y-4)

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Solution for 8(4y-3)=2(11y-4) equation: 



8(4y-3)=2(11y-4)

We move all terms to the left:

8(4y-3)-(2(11y-4))=0

We multiply parentheses

32y-(2(11y-4))-24=0



We calculate terms in parentheses: -(2(11y-4)), so:

2(11y-4)

We multiply parentheses

22y-8

Back to the equation:

-(22y-8)



We get rid of parentheses

32y-22y+8-24=0

We add all the numbers together, and all the variables

10y-16=0

We move all terms containing y to the left, all other terms to the right

10y=16

y=16/10

y=1+3/5

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