(4y+3)=(7y-18)

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Solution for (4y+3)=(7y-18) equation: 



(4y+3)=(7y-18)

We move all terms to the left:

(4y+3)-((7y-18))=0

We get rid of parentheses

4y-((7y-18))+3=0



We calculate terms in parentheses: -((7y-18)), so:

(7y-18)

We get rid of parentheses

7y-18

Back to the equation:

-(7y-18)



We get rid of parentheses

4y-7y+18+3=0

We add all the numbers together, and all the variables

-3y+21=0

We move all terms containing y to the left, all other terms to the right

-3y=-21

y=-21/-3

y=+7

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