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(4x^2-2x+8)-(x2+3x-2)=
We move all terms to the left:
(4x^2-2x+8)-(x2+3x-2)-()=0
We add all the numbers together, and all the variables
-(+x^2+3x-2)+(4x^2-2x+8)-()=0
We add all the numbers together, and all the variables
-(+x^2+3x-2)+(4x^2-2x+8)=0
We get rid of parentheses
-x^2+4x^2-3x-2x+2+8=0
We add all the numbers together, and all the variables
3x^2-5x+10=0
a = 3; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·3·10
Δ = -95
Delta is less than zero, so there is no solution for the equation
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