50+2(4z-5)=100

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Solution for 50+2(4z-5)=100 equation: 



50+2(4z-5)=100

We move all terms to the left:

50+2(4z-5)-(100)=0

We add all the numbers together, and all the variables

2(4z-5)-50=0

We multiply parentheses

8z-10-50=0

We add all the numbers together, and all the variables

8z-60=0

We move all terms containing z to the left, all other terms to the right

8z=60

z=60/8

z=7+1/2

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