(4x2)=(3x2+25)

Solution for (4x2)=(3x2+25) equation:

(4x^2)=(3x^2+25)

We move all terms to the left:

(4x^2)-((3x^2+25))=0


We calculate terms in parentheses: -((3x^2+25)), so:

(3x^2+25)

We get rid of parentheses

3x^2+25

Back to the equation:

-(3x^2+25)


We get rid of parentheses

4x^2-3x^2-25=0

We add all the numbers together, and all the variables

x^2-25=0

a = 1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·1·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*1}=\frac{10}{2}
=5
$