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6(3x-1)=3(x+3)
We move all terms to the left:
6(3x-1)-(3(x+3))=0
We multiply parentheses
18x-(3(x+3))-6=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
18x-3x-9-6=0
We add all the numbers together, and all the variables
15x-15=0
We move all terms containing x to the left, all other terms to the right
15x=15
x=15/15
x=1
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