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(4x/5+32)=(2x-28)
We move all terms to the left:
(4x/5+32)-((2x-28))=0
We get rid of parentheses
4x/5-((2x-28))+32=0
We multiply all the terms by the denominator
4x-(((2x-28)))*5+32*5=0
We add all the numbers together, and all the variables
4x-(((2x-28)))*5+160=0
We move all terms containing x to the left, all other terms to the right
4x-(((2x-28)))*5=-160
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