-4(2x-5)+2(3x-2)=4(3x-1)

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Solution for -4(2x-5)+2(3x-2)=4(3x-1) equation: 



-4(2x-5)+2(3x-2)=4(3x-1)

We move all terms to the left:

-4(2x-5)+2(3x-2)-(4(3x-1))=0

We multiply parentheses

-8x+6x-(4(3x-1))+20-4=0



We calculate terms in parentheses: -(4(3x-1)), so:

4(3x-1)

We multiply parentheses

12x-4

Back to the equation:

-(12x-4)



We add all the numbers together, and all the variables

-2x-(12x-4)+16=0

We get rid of parentheses

-2x-12x+4+16=0

We add all the numbers together, and all the variables

-14x+20=0

We move all terms containing x to the left, all other terms to the right

-14x=-20

x=-20/-14

x=1+3/7

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