(4x-8)=1/5(35x=30)

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Solution for (4x-8)=1/5(35x=30) equation: 



(4x-8)=1/5(35x=30)

We move all terms to the left:

(4x-8)-(1/5(35x)=0



Domain of the equation: 535x!=0

x!=0/535

x!=0

x∈R



We get rid of parentheses

4x-(1/535x-8=0

We multiply all the terms by the denominator


4x*535x-8-(1=0

We add all the numbers together, and all the variables

4x*535x=0

Wy multiply elements

2140x^2=0

a = 2140; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2140·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4280}=0$

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