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1/2x-3=2-3/5x
We move all terms to the left:
1/2x-3-(2-3/5x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-(-3/5x+2)-3=0
We get rid of parentheses
1/2x+3/5x-2-3=0
We calculate fractions
5x/10x^2+6x/10x^2-2-3=0
We add all the numbers together, and all the variables
5x/10x^2+6x/10x^2-5=0
We multiply all the terms by the denominator
5x+6x-5*10x^2=0
We add all the numbers together, and all the variables
11x-5*10x^2=0
Wy multiply elements
-50x^2+11x=0
a = -50; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-50)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-50}=\frac{-22}{-100} =11/50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-50}=\frac{0}{-100} =0 $
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