(4x-7)+(40-x)=90

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Solution for (4x-7)+(40-x)=90 equation: 



(4x-7)+(40-x)=90

We move all terms to the left:

(4x-7)+(40-x)-(90)=0

We add all the numbers together, and all the variables

(4x-7)+(-1x+40)-90=0

We get rid of parentheses

4x-1x-7+40-90=0

We add all the numbers together, and all the variables

3x-57=0

We move all terms containing x to the left, all other terms to the right

3x=57

x=57/3

x=19

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