(4x-6)(7x+2)=0

Solution for (4x-6)(7x+2)=0 equation:

(4x-6)(7x+2)=0

We multiply parentheses ..

(+28x^2+8x-42x-12)=0

We get rid of parentheses

28x^2+8x-42x-12=0

We add all the numbers together, and all the variables

28x^2-34x-12=0

a = 28; b = -34; c = -12;
Δ = b2-4ac
Δ = -342-4·28·(-12)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-50}{2*28}=\frac{-16}{56}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+50}{2*28}=\frac{84}{56}
=1+1/2
$