2(3y+1)-(y-2)=14

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Solution for 2(3y+1)-(y-2)=14 equation: 



2(3y+1)-(y-2)=14

We move all terms to the left:

2(3y+1)-(y-2)-(14)=0

We multiply parentheses

6y-(y-2)+2-14=0

We get rid of parentheses

6y-y+2+2-14=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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