(4x-5)+(3x+30)+(8x-40)=180

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Solution for (4x-5)+(3x+30)+(8x-40)=180 equation: 



(4x-5)+(3x+30)+(8x-40)=180

We move all terms to the left:

(4x-5)+(3x+30)+(8x-40)-(180)=0

We get rid of parentheses

4x+3x+8x-5+30-40-180=0

We add all the numbers together, and all the variables

15x-195=0

We move all terms containing x to the left, all other terms to the right

15x=195

x=195/15

x=13

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