4(2m-3)-20=5(m+4)+7m

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Solution for 4(2m-3)-20=5(m+4)+7m equation: 



4(2m-3)-20=5(m+4)+7m

We move all terms to the left:

4(2m-3)-20-(5(m+4)+7m)=0

We multiply parentheses

8m-(5(m+4)+7m)-12-20=0



We calculate terms in parentheses: -(5(m+4)+7m), so:

5(m+4)+7m

We add all the numbers together, and all the variables

7m+5(m+4)

We multiply parentheses

7m+5m+20

We add all the numbers together, and all the variables

12m+20

Back to the equation:

-(12m+20)



We add all the numbers together, and all the variables

8m-(12m+20)-32=0

We get rid of parentheses

8m-12m-20-32=0

We add all the numbers together, and all the variables

-4m-52=0

We move all terms containing m to the left, all other terms to the right

-4m=52

m=52/-4

m=-13

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