(4x-30)+(2x+25)+(X+50)+(X+40)=(2X-5)

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Solution for (4x-30)+(2x+25)+(X+50)+(X+40)=(2X-5) equation: 



(4x-30)+(2x+25)+(x+50)+(x+40)=(2x-5)

We move all terms to the left:

(4x-30)+(2x+25)+(x+50)+(x+40)-((2x-5))=0

We get rid of parentheses

4x+2x+x+x-((2x-5))-30+25+50+40=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

8x-(2x-5)+85=0

We get rid of parentheses

8x-2x+5+85=0

We add all the numbers together, and all the variables

6x+90=0

We move all terms containing x to the left, all other terms to the right

6x=-90

x=-90/6

x=-15

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