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22c(10-c)+15c=199
We move all terms to the left:
22c(10-c)+15c-(199)=0
We add all the numbers together, and all the variables
22c(-1c+10)+15c-199=0
We add all the numbers together, and all the variables
15c+22c(-1c+10)-199=0
We multiply parentheses
-22c^2+15c+220c-199=0
We add all the numbers together, and all the variables
-22c^2+235c-199=0
a = -22; b = 235; c = -199;
Δ = b2-4ac
Δ = 2352-4·(-22)·(-199)
Δ = 37713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(235)-\sqrt{37713}}{2*-22}=\frac{-235-\sqrt{37713}}{-44} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(235)+\sqrt{37713}}{2*-22}=\frac{-235+\sqrt{37713}}{-44} $
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