(4x-3)/2=(5+6x)/5

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Solution for (4x-3)/2=(5+6x)/5 equation: 



(4x-3)/2=(5+6x)/5

We move all terms to the left:

(4x-3)/2-((5+6x)/5)=0

We add all the numbers together, and all the variables

(4x-3)/2-((6x+5)/5)=0

We calculate fractions


4x/()+(-((6x+5)*2)/()=0



We calculate terms in parentheses: +(-((6x+5)*2)/(), so:

-((6x+5)*2)/(

We multiply all the terms by the denominator


-((6x+5)*2)



We calculate terms in parentheses: -((6x+5)*2), so:

(6x+5)*2

We multiply parentheses

12x+10

Back to the equation:

-(12x+10)



We get rid of parentheses

-12x-10

Back to the equation:

+(-12x-10)



We get rid of parentheses

4x/()-12x-10=0

We multiply all the terms by the denominator


4x-12x*()-10*()=0

We add all the numbers together, and all the variables

4x-12x*()=0

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