Z-4+z=2(z+2)

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Solution for Z-4+z=2(z+2) equation:



-4+Z=2(Z+2)
We move all terms to the left:
-4+Z-(2(Z+2))=0
We calculate terms in parentheses: -(2(Z+2)), so:
2(Z+2)
We multiply parentheses
2Z+4
Back to the equation:
-(2Z+4)
We get rid of parentheses
Z-2Z-4-4=0
We add all the numbers together, and all the variables
-1Z-8=0
We move all terms containing Z to the left, all other terms to the right
-Z=8
Z=8/-1
Z=-8

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