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(4x-12/6)=(2x+14/13)
We move all terms to the left:
(4x-12/6)-((2x+14/13))=0
We add all the numbers together, and all the variables
(4x-2)-((+2x+14/13))=0
We get rid of parentheses
4x-((+2x+14/13))-2=0
We multiply all the terms by the denominator
4x*13))-((+2x+14-2*13))=0
We add all the numbers together, and all the variables
4x*13))-((2x-12))=0
We add all the numbers together, and all the variables
4x*13))-((2x=0
Wy multiply elements
52x^2=0
a = 52; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·52·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{104}=0$
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