(4x-10)/12-x/4=x/12+4

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Solution for (4x-10)/12-x/4=x/12+4 equation: 


x in (-oo:+oo)

(4*x-10)/12-(x/4) = x/12+4 // - x/12+4

(4*x-10)/12-(x/4)-(x/12)-4 = 0

(4*x-10)/12-x/4-x/12-4 = 0

(4*(4*x-10))/(4*12)+(12*(-x))/(4*12)+(4*(-x))/(4*12)+(-4*4*12)/(4*12) = 0

4*(4*x-10)+12*(-x)+4*(-x)-4*4*12 = 0

4*x-4*x-192-40 = 0

-192-40 = 0

-232 = 0

-232/(4*12) = 0

-232/(4*12) = 0 // * 4*12

-232 = 0

x belongs to the empty set

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