9(3y+5)(y+3)/27(y-2)(3y+5)

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Solution for 9(3y+5)(y+3)/27(y-2)(3y+5) equation: 


y in (-oo:+oo)

((9*(3*y+5)*(y+3))/27)*(y-2)*(3*y+5) = 0

(9*(3*y+5)^2*(y+3)*(y-2))/27 = 0

( 3*y+5 )

3*y+5 = 0 // - 5

3*y = -5 // : 3

y = -5/3

( y+3 )

y+3 = 0 // - 3

y = -3

( y-2 )

y-2 = 0 // + 2

y = 2

y in { -5/3, -5/3, -3, 2 }

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