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(4x-1)(5x+7)=0
We multiply parentheses ..
(+20x^2+28x-5x-7)=0
We get rid of parentheses
20x^2+28x-5x-7=0
We add all the numbers together, and all the variables
20x^2+23x-7=0
a = 20; b = 23; c = -7;
Δ = b2-4ac
Δ = 232-4·20·(-7)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-33}{2*20}=\frac{-56}{40} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+33}{2*20}=\frac{10}{40} =1/4 $
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