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(4x-1)(2x-6)=0
We multiply parentheses ..
(+8x^2-24x-2x+6)=0
We get rid of parentheses
8x^2-24x-2x+6=0
We add all the numbers together, and all the variables
8x^2-26x+6=0
a = 8; b = -26; c = +6;
Δ = b2-4ac
Δ = -262-4·8·6
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-22}{2*8}=\frac{4}{16} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+22}{2*8}=\frac{48}{16} =3 $
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