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(2x+3)(5x-10)=0
We multiply parentheses ..
(+10x^2-20x+15x-30)=0
We get rid of parentheses
10x^2-20x+15x-30=0
We add all the numbers together, and all the variables
10x^2-5x-30=0
a = 10; b = -5; c = -30;
Δ = b2-4ac
Δ = -52-4·10·(-30)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*10}=\frac{-30}{20} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*10}=\frac{40}{20} =2 $
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