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(4x+6/x-3)-(25x+75/2x+5)=5
We move all terms to the left:
(4x+6/x-3)-(25x+75/2x+5)-(5)=0
Domain of the equation: x-3)!=0
x∈R
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
4x+6/x-25x-75/2x-3-5-5=0
We calculate fractions
4x-25x+12x/2x^2+(-75x)/2x^2-3-5-5=0
We add all the numbers together, and all the variables
-21x+12x/2x^2+(-75x)/2x^2-13=0
We multiply all the terms by the denominator
-21x*2x^2+12x+(-75x)-13*2x^2=0
We add all the numbers together, and all the variables
12x-21x*2x^2+(-75x)-13*2x^2=0
Wy multiply elements
-42x^3-26x^2+12x+(-75x)=0
We get rid of parentheses
-42x^3-26x^2+12x-75x=0
We do not support expression: x^3
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