(4x+4)+(4x+3)+(4x)=(4x)+(4x)+(5x+1)

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Solution for (4x+4)+(4x+3)+(4x)=(4x)+(4x)+(5x+1) equation: 



(4x+4)+(4x+3)+(4x)=(4x)+(4x)+(5x+1)

We move all terms to the left:

(4x+4)+(4x+3)+(4x)-((4x)+(4x)+(5x+1))=0

We add all the numbers together, and all the variables

4x+(4x+4)+(4x+3)-(4x+4x+(5x+1))=0

We get rid of parentheses

4x+4x+4x-(4x+4x+(5x+1))+4+3=0



We calculate terms in parentheses: -(4x+4x+(5x+1)), so:

4x+4x+(5x+1)

We add all the numbers together, and all the variables

8x+(5x+1)

We get rid of parentheses

8x+5x+1

We add all the numbers together, and all the variables

13x+1

Back to the equation:

-(13x+1)



We add all the numbers together, and all the variables

12x-(13x+1)+7=0

We get rid of parentheses

12x-13x-1+7=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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