12x-3(2x+3)+4=4x+5(x-8)-4

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Solution for 12x-3(2x+3)+4=4x+5(x-8)-4 equation: 



12x-3(2x+3)+4=4x+5(x-8)-4

We move all terms to the left:

12x-3(2x+3)+4-(4x+5(x-8)-4)=0

We multiply parentheses

12x-6x-(4x+5(x-8)-4)-9+4=0



We calculate terms in parentheses: -(4x+5(x-8)-4), so:

4x+5(x-8)-4

We multiply parentheses

4x+5x-40-4

We add all the numbers together, and all the variables

9x-44

Back to the equation:

-(9x-44)



We add all the numbers together, and all the variables

6x-(9x-44)-5=0

We get rid of parentheses

6x-9x+44-5=0

We add all the numbers together, and all the variables

-3x+39=0

We move all terms containing x to the left, all other terms to the right

-3x=-39

x=-39/-3

x=+13

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