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(4x+30)2x=360
We move all terms to the left:
(4x+30)2x-(360)=0
We multiply parentheses
8x^2+60x-360=0
a = 8; b = 60; c = -360;
Δ = b2-4ac
Δ = 602-4·8·(-360)
Δ = 15120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15120}=\sqrt{144*105}=\sqrt{144}*\sqrt{105}=12\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{105}}{2*8}=\frac{-60-12\sqrt{105}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{105}}{2*8}=\frac{-60+12\sqrt{105}}{16} $
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