12x=3x2-96

Solution for 12x=3x2-96 equation:

12x=3x^2-96

We move all terms to the left:

12x-(3x^2-96)=0

We get rid of parentheses

-3x^2+12x+96=0

a = -3; b = 12; c = +96;
Δ = b2-4ac
Δ = 122-4·(-3)·96
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*-3}=\frac{-48}{-6}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*-3}=\frac{24}{-6}
=-4
$