(4x+3)/5=(2x-1)/2

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Solution for (4x+3)/5=(2x-1)/2 equation: 


x in (-oo:+oo)

(4*x+3)/5 = (2*x-1)/2 // - (2*x-1)/2

(4*x+3)/5-((2*x-1)/2) = 0

(4*x+3)/5+(-1*(2*x-1))/2 = 0

(2*(4*x+3))/(2*5)+(-1*5*(2*x-1))/(2*5) = 0

2*(4*x+3)-1*5*(2*x-1) = 0

11-2*x = 0

(11-2*x)/(2*5) = 0

(11-2*x)/(2*5) = 0 // * 2*5

11-2*x = 0

11-2*x = 0 // - 11

-2*x = -11 // : -2

x = -11/(-2)

x = 11/2

x = 11/2

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