(4x+3)+4x=1-2(4+6x)

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Solution for (4x+3)+4x=1-2(4+6x) equation: 



(4x+3)+4x=1-2(4+6x)

We move all terms to the left:

(4x+3)+4x-(1-2(4+6x))=0

We add all the numbers together, and all the variables

(4x+3)+4x-(1-2(6x+4))=0

We add all the numbers together, and all the variables

4x+(4x+3)-(1-2(6x+4))=0

We get rid of parentheses

4x+4x-(1-2(6x+4))+3=0



We calculate terms in parentheses: -(1-2(6x+4)), so:

1-2(6x+4)

determiningTheFunctionDomain
-2(6x+4)+1

We multiply parentheses

-12x-8+1

We add all the numbers together, and all the variables

-12x-7

Back to the equation:

-(-12x-7)



We add all the numbers together, and all the variables

8x-(-12x-7)+3=0

We get rid of parentheses

8x+12x+7+3=0

We add all the numbers together, and all the variables

20x+10=0

We move all terms containing x to the left, all other terms to the right

20x=-10

x=-10/20

x=-1/2

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