(m+2)(m+3)=(m+2)(m-2

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Solution for (m+2)(m+3)=(m+2)(m-2 equation: 



(m+2)(m+3)=(m+2)(m-2

We move all terms to the left:

(m+2)(m+3)-((m+2)(m-2)=0

We use the square of the difference formula

m^2+(m+2)(m+3)+4=0

We multiply parentheses ..

m^2+(+m^2+3m+2m+6)+4=0

We get rid of parentheses

m^2+m^2+3m+2m+6+4=0

We add all the numbers together, and all the variables

2m^2+5m+10=0

a = 2; b = 5; c = +10;
Δ = b2-4ac
Δ = 52-4·2·10
Δ = -55
Delta is less than zero, so there is no solution for the equation

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