(4x+3)+12x=131

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Solution for (4x+3)+12x=131 equation: 



(4x+3)+12x=131

We move all terms to the left:

(4x+3)+12x-(131)=0

We add all the numbers together, and all the variables

12x+(4x+3)-131=0

We get rid of parentheses

12x+4x+3-131=0

We add all the numbers together, and all the variables

16x-128=0

We move all terms containing x to the left, all other terms to the right

16x=128

x=128/16

x=8

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