(4x+3)+(3x-2)=90

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Solution for (4x+3)+(3x-2)=90 equation: 



(4x+3)+(3x-2)=90

We move all terms to the left:

(4x+3)+(3x-2)-(90)=0

We get rid of parentheses

4x+3x+3-2-90=0

We add all the numbers together, and all the variables

7x-89=0

We move all terms containing x to the left, all other terms to the right

7x=89

x=89/7

x=12+5/7

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