(4x+3)+(3x-2)=180

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Solution for (4x+3)+(3x-2)=180 equation: 



(4x+3)+(3x-2)=180

We move all terms to the left:

(4x+3)+(3x-2)-(180)=0

We get rid of parentheses

4x+3x+3-2-180=0

We add all the numbers together, and all the variables

7x-179=0

We move all terms containing x to the left, all other terms to the right

7x=179

x=179/7

x=25+4/7

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