(4x+3)*(6x-5)=(2x+3)*(12x-13)

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Solution for (4x+3)*(6x-5)=(2x+3)*(12x-13) equation: 



(4x+3)(6x-5)=(2x+3)(12x-13)

We move all terms to the left:

(4x+3)(6x-5)-((2x+3)(12x-13))=0

We multiply parentheses ..

(+24x^2-20x+18x-15)-((2x+3)(12x-13))=0



We calculate terms in parentheses: -((2x+3)(12x-13)), so:

(2x+3)(12x-13)

We multiply parentheses ..

(+24x^2-26x+36x-39)

We get rid of parentheses

24x^2-26x+36x-39

We add all the numbers together, and all the variables

24x^2+10x-39

Back to the equation:

-(24x^2+10x-39)



We get rid of parentheses

24x^2-24x^2-20x+18x-10x-15+39=0

We add all the numbers together, and all the variables

-12x+24=0

We move all terms containing x to the left, all other terms to the right

-12x=-24

x=-24/-12

x=+2

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