9y+3y-12=3(4y-4)

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Solution for 9y+3y-12=3(4y-4) equation: 



9y+3y-12=3(4y-4)

We move all terms to the left:

9y+3y-12-(3(4y-4))=0

We add all the numbers together, and all the variables

12y-(3(4y-4))-12=0



We calculate terms in parentheses: -(3(4y-4)), so:

3(4y-4)

We multiply parentheses

12y-12

Back to the equation:

-(12y-12)



We get rid of parentheses

12y-12y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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