(4x+3)(x-4)=(4x+3)(x-3)

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Solution for (4x+3)(x-4)=(4x+3)(x-3) equation: 



(4x+3)(x-4)=(4x+3)(x-3)

We move all terms to the left:

(4x+3)(x-4)-((4x+3)(x-3))=0

We multiply parentheses ..

(+4x^2-16x+3x-12)-((4x+3)(x-3))=0



We calculate terms in parentheses: -((4x+3)(x-3)), so:

(4x+3)(x-3)

We multiply parentheses ..

(+4x^2-12x+3x-9)

We get rid of parentheses

4x^2-12x+3x-9

We add all the numbers together, and all the variables

4x^2-9x-9

Back to the equation:

-(4x^2-9x-9)



We get rid of parentheses

4x^2-4x^2-16x+3x+9x-12+9=0

We add all the numbers together, and all the variables

-4x-3=0

We move all terms containing x to the left, all other terms to the right

-4x=3

x=3/-4

x=-3/4

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