1/(2x+1)-1/(3x+1)=3

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Solution for 1/(2x+1)-1/(3x+1)=3 equation: 



1/(2x+1)-1/(3x+1)=3

We move all terms to the left:

1/(2x+1)-1/(3x+1)-(3)=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R





Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R



We calculate fractions


(1*(3x+1))/((2x+1)*(3x+1))+(-1*(2x+1))/((2x+1)*(3x+1))-3=0



We calculate terms in parentheses: +(1*(3x+1))/((2x+1)*(3x+1)), so:

1*(3x+1))/((2x+1)*(3x+1)

We multiply all the terms by the denominator


1*(3x+1))

Back to the equation:

+(1*(3x+1)))





We calculate terms in parentheses: +(-1*(2x+1))/((2x+1)*(3x+1)), so:

-1*(2x+1))/((2x+1)*(3x+1)

We multiply all the terms by the denominator


-1*(2x+1))

Back to the equation:

+(-1*(2x+1)))

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