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(4x+3)(3x+2)=122
We move all terms to the left:
(4x+3)(3x+2)-(122)=0
We multiply parentheses ..
(+12x^2+8x+9x+6)-122=0
We get rid of parentheses
12x^2+8x+9x+6-122=0
We add all the numbers together, and all the variables
12x^2+17x-116=0
a = 12; b = 17; c = -116;
Δ = b2-4ac
Δ = 172-4·12·(-116)
Δ = 5857
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{5857}}{2*12}=\frac{-17-\sqrt{5857}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{5857}}{2*12}=\frac{-17+\sqrt{5857}}{24} $
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