(x-7)(x-5)(x+4)(x+6)=506

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Solution for (x-7)(x-5)(x+4)(x+6)=506 equation: 



(x-7)(x-5)(x+4)(x+6)=506

We move all terms to the left:

(x-7)(x-5)(x+4)(x+6)-(506)=0

We multiply parentheses ..

(+x^2-5x-7x+35)(x+4)(x+6)-506=0

We multiply parentheses ..

(+x^2-5x-7x+35)(+x^2+6x+4x+24)-506=0

We move all terms containing x to the left, all other terms to the right

(+x^2-5x-7x+35)(+x^2+6x+4x+24)=506

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