(4x+3)(22+x)=360

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Solution for (4x+3)(22+x)=360 equation:



(4x+3)(22+x)=360
We move all terms to the left:
(4x+3)(22+x)-(360)=0
We add all the numbers together, and all the variables
(4x+3)(x+22)-360=0
We multiply parentheses ..
(+4x^2+88x+3x+66)-360=0
We get rid of parentheses
4x^2+88x+3x+66-360=0
We add all the numbers together, and all the variables
4x^2+91x-294=0
a = 4; b = 91; c = -294;
Δ = b2-4ac
Δ = 912-4·4·(-294)
Δ = 12985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12985}=\sqrt{49*265}=\sqrt{49}*\sqrt{265}=7\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-7\sqrt{265}}{2*4}=\frac{-91-7\sqrt{265}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+7\sqrt{265}}{2*4}=\frac{-91+7\sqrt{265}}{8} $

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