(5z+3)(1-z)=0

Solution for (5z+3)(1-z)=0 equation:

(5z+3)(1-z)=0

We add all the numbers together, and all the variables

(5z+3)(-1z+1)=0

We multiply parentheses ..

(-5z^2+5z-3z+3)=0

We get rid of parentheses

-5z^2+5z-3z+3=0

We add all the numbers together, and all the variables

-5z^2+2z+3=0

a = -5; b = 2; c = +3;
Δ = b2-4ac
Δ = 22-4·(-5)·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*-5}=\frac{-10}{-10}
=1
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*-5}=\frac{6}{-10}
=-3/5
$