(4x+2)(2x+8)=0

Solution for (4x+2)(2x+8)=0 equation:

(4x+2)(2x+8)=0

We multiply parentheses ..

(+8x^2+32x+4x+16)=0

We get rid of parentheses

8x^2+32x+4x+16=0

We add all the numbers together, and all the variables

8x^2+36x+16=0

a = 8; b = 36; c = +16;
Δ = b2-4ac
Δ = 362-4·8·16
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-28}{2*8}=\frac{-64}{16}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+28}{2*8}=\frac{-8}{16}
=-1/2
$